Question

1.A new galvanic cell of E°cell more than E°cell of Daniel cell is connected to Daniel cell in a manner that new cell gives electrons to cathode, what will happen
1 point
Daniel cell will work as electrolytic cell where Zn will be deposite on zinc rod and copper will dissolve from copper rod.
Ecell will increase
Ecell will decrease
No change will take place

Answer 1

Answer:

Deniel cell will work as electrolytic cell where zn will be deposited on zn rod and copper will dissolve from copper rod.

Answer 2

A correct answer is an option (1) Daniel's cell will work as an electrolytic cell where Zn will be deposited on a zinc rod and copper will dissolve from the copper rod.

EXPLANATION

• It Is provided that the electromotive force of the galvanic cell is more than the Emf of the Daniel cell (>1.1V).
• When The galvanic cell gives electrons to the cathode following changes can take place -
• The flow of current is reversed.
• That is, the Anode behaves as Cathode and the vice verse.
• Therefore, Zinc gets deposited on the zinc rod from the solution and copper ions get dissolved into the solution.
• A Daniel cell is a type of electrochemical cell that carries out chemical reactions to supply energy.
• A Daniel cell is represented as -

Zn|Zn⁺²(aq) || Cu⁺²(aq)|Cu

• Anode reaction of Daniel cell -

Zn(s) --------> Zn⁺² + 2e-

(Zinc metal is oxidized at the cathode)

• Cathode reaction of Daniel cell.

Cu⁺² + 2e⁻ ----------> Cu(s)

• When an external potential difference is connected to the daniel cell, the Following reaction place-

At cathode

Zn⁺² + 2e⁻ -------> Zn(s)

At Anode

Cu(s) ---------> Cu⁺⁺ + 2e⁻.

Hence, the correct answer is option (1)

#Spj2