Question

1. A number consists of three digits of
which the middle one is zero and their
sum is 4. If the number formed by
interchanging the first and last digits is
greater than the number itself by 198,
then the difference between the first and
last digits is
(a) 1
(b) 2
(d) 4
(c)
3​

Answer 1

Answer:

2

Step-by-step explanation:

Let the required number be abc which can also be written as 100a + 10b + c.

As given middle term of the number is 0 so 10b = 0 = > b = 0.

So the number is 100a + 0 + c = 100a + c

When the digits are reversed, new number is cba or 100c + 10b + a = > 100c + a.

According to the question :

= > Original number = new number + 198

= > 100a + c = 100c + a + 198

= > 100a - a + c - 100c = 198

= > 99a - 99c = 198

= > 99( a - c ) = 198

= > a - c = 2

= > Difference between first and last digit = 2