Question

1. A number is 12 more than the other. Find the numbers if their sum is 48.
2. Twice the number decreased by 22 is 48. Find the number.
3. The sum of three consecutive odd numbers is 51. Find the numbers.

Solve with proper working

First and the correct answer will be marked as brainliest.

Answer 1

Answer:

Step-by-step explanation:

Consecutive odd numbers (x=smallest): x, x+2, x+4

3x-7 = "three times the smallest … decreased by 7"

2(x+4) = "twice the largest"

These two things are equal: 3x-7 = 2(x+4)

3x-7 = 2x+8

x = 15

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Ans: the 3 numbers are 15, 17, and 19

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Check: 3(15)-7 = 45-7 = 38

2(19) = 38 √

Mark it as brainliest

Answer 2

1):
A+A+12=48,

2A=48-12,

2A=36,

A=18,

then
second number=18+12=30,

2):-

2A-22=48,

2A=48+22,

2A=70,

A=35,


3):-

x + x+2 + x+4=51,

3x+6=51,

3x=51-6,

3x=45,

x=15,

15,(15+2) and (15+4),

15,17,19