Question

1. A number is divided by 17 leaves remainder 7 find the least number to be subtracted from this number to make it divisible by 17
2.A number divided by 15 leaves remainder 6.find the least positive number to be added to this number to make it divisible by 15

Answer 1

1) 7 only

2) we have 6+X=15

what is it yes 9

Answer 2

Answer:

the answer is 17

Step-by-step explanation:

let number be = x

divisor=17

quotient=?   (let it be q)

remainder = 7

according to euclid division lemma

here, a=dividend        b=divisor     q=quotient      r=remainder

a=bq+r                     where 0 ≤ r  >  b

a=17q+7

a-7=17q

a-7/17=q

hence, if 7 is subracted from a

a is perfectly divisible by 17

therefore the least number is 7