Question

1.A nut can be opened by lever of length 15cm. If the minimum force required is 6N, calculate the moment of force to turn the nut.​

Answer 1

Explanation:

Moment of force= distance* force

Force=6N

Distance= 15cm=0.15m

6N*0.15m=0. 90Nm

Answer 2

Given that we are applying a force of 5 N and a nut is opened by a wrench of length 10cm ( is also equal to 0.1 m). Moment of force is given by formula r×F. Hence 0.1×5=0.5N−m. Hence moment of force is 0.5Nm.