Question

(1) ((A'OB' ) AN
(ii) [B' (B' - A) }
(ui) (A-1B)-(B-C)
(iv) (A-B) n (C-B)
(v) & & AX (BNC)
@ (AXB) n (AXC)
@ LAX B)U (AXC)
(f) (Anc)-B
(vi) a AX(BUC)​

Answer 1

Answer:

what we have to do......