Question

1. A paper is in the form of a rectangle PQRS in which PQ = 30 cm and QR = 21
cm.Q semicircular portion with QR as diameter is cut-off. Find the area of the
remaining part.​

Answer 1

Answer:

ANSWER

We have,

AB=CD=30 cm

AD=BC=20 cm

Since,

ABCD is a rectangle and semicircular portion with BC diameter is cut off. it means radius of semicircle is 10 cm.

Therefore, the area of remaining part is

=AB×AD−

2

π×(BC/2)

2

=30×20−

2

π×(20/2)

2

=600−

2

π×(10)

2

=600−

2

π×100

=600−3.14×50

=600−157

=443 cm

2

Hence, this is the answer.