Question

1. A Parallel Plate capacitor has following dimensions Distance between the
plates=10cm Area of Plate=2 m Charge on each plate=8.85x10-10 C
Calculate following:
a) Electric Field Between the plates
b) Capacitance of the capacitor
c) Energy stored in the capacitor​

Answer 1

Answer:

E=

∈

0

σ

=

A∈

0

Q

Q=AE∈

0

Q=(1)(100)(8.85×10

−12

)

Q=8.85×10

−19

C