Question

1.
A particle executes SHM with an equation of motion given by
x(t) = (20.0cm ) cos(12nrad /s) -- rad
(A) Magnitude of maximum velocity of particle is 240 a cm/s
(B) Magnitude of maximum acceleration of particle is 2880 12 cm/s2
(C) Displacement of the particle from its mean position will be minimum at t =
1
S
36
2.
(D) Net force acting on the particle will be minimum at t = sec
72
A particle executes simple harmonic motion of time period T. At t = 0, it is at
towards positive amplitude then :-

Answer 1

Answer:

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