Question

1.
A particle has initial velocity 10 m/s. It moves
due to constant retarding force along the line of
velocity which produces a retardation of 5 m/s?.
Then
(a) the maximum displacement in the direction of
initial velocity is 10 m
(b) the distance travelled in first 3 seconds is 7.5 m
(c) the distance travelled in first 3 seconds is
12.5 m
(d) the distance travelled in first 3 seconds is
17.5 m.​

Answer 1

$\huge\bold{HEY:)-}$

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“Your preparation for the real world is not in the answers you’ve learned, but in the questions you’ve learned how to ask yourself"

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Answer = (c)

Solution

↪The displacement of the particle is till the final velocity becomes zero. so,applying

v^2-u^2=2a s we get s=10m

Now, frm the equation s=ut - 1/2a t^2 we get that final velocity becomes zero at time t=2 sec

So the distance travelled is

s(at 3rd sec)+10=u - a/2(2n-1) [here n is 3]

after putting all the values we get

s=12.5m

⤵⤵⤵⤵

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Answer 2

Answer:

A AND C ARE CORRECT

Explanation: