Question

1
A particle is moving with constant initial velocity
4 ms-1 till t=1.5s. Then it accelerates at
10 ms-2 from 1.5 s to 3 s. The distance covered
is
(1) 17.25 m
(2) 36.25 m
(3) 40 m
(4) 23.25 m​

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial velocity of particle, u = 4 m/s

Acceleration by particle, a = 2 m/s

Time taken by particle, t = 1.5 s

To Find,

Distance covered, s = ?

According to 2nd equation of motion,

We know that,

s = ut + 1/2 at²

So, putting all the values, we get

s = ut + 1/2 at²

⇒ s = 4 × 1.5 + 1/2 × 2 × 1.5²

⇒ s = 6 + 1/2 × 2 × 2.5

⇒ s = 6 + 1/2 × 5

⇒ s = 6 + 2.5

⇒ s = 8.5 m

Hence, the distance covered by particle is 8.5 m.

Answer 2

Answer:

answer is brainly is a sh!tty website and the moderators are drunk, because you can clearly see the answer above mine is totally wrong as it isnt giving answer from the list just thrown some random answer and it has got that fake expert verified mark

Explanatiaon: