Question

1. A particle is thrown vertically upward. Its velocity at half of the height is
10m/s, then maximum height attained by it is (g=10m/s)​

Answer 1

Answer:

10 m

Explanation:

For half height,

10^2 = u^2−2gh/2...(i)

For total height,

0 = u^2−2gh ...(ii)

From (i) and (ii)

⇒10^2=2gh/2⇒h=10m