Question

1. A particle is thrown vertically upwards with velocity
30 ms^(-1). Find the ratio of average speed and
speed after 6 seconds. Take g = 10ms^(-1)
a)1/2
b)1
c)3/2
d) 2
​

Answer 1

Answer:

3/2 is the correct answer

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Answer 2

The correct option is (A) 1/2.

Explanation: Vo = 30 m/s

t = 6 s

V = Vo + at

hence after 6s,

V = 30 + (10× 6)

= 90 m/s

i.e. velocity after 6 sec = 90 m/s

average speed = {(2v,v2) / (V1 + V2)}

= {(2v,V) / (Vo + v)}

= [{2(30) (90)} / {30 + 90}]

= 45 m/s

ratio= {(average speed) / (instantaneous velocity)}

=(45 / 90)

= (1/2)

Hope this will help :)