Question

1.A particle ismoving up an inclined plane .Its velocity changes from 15m/s to 10m/s in two seconds . What is its acceleration?

Answer 1

Answer

• Acceleration = - 2.5 m/s²

Given

• A particle is moving up an inclined plane .Its velocity changes from 15 m/s to 10 m/s in two seconds

To Find

• Acceleration

Concept Used

Acceleration

• It is defined as rate of change in velocity

$\bigstar \bf \;\;\; Acceleration=\dfrac{Change\ in\ velocity}{Time}$

• SI unit of Acceleration is m/s²
• SI unit of velocity is m/s
• SI unit of Time is second

Solution

Initial velocity , u = 15 m/s

Final velocity , v = 10 m/s

Time , t = 2 s

Acceleration , a = ? m/s²

Now , Apply formula .

$\implies \rm Acceleration=\dfrac{Change\ in\ velocity}{Time}\\\\\implies \rm a=\dfrac{v-u}{t}\\\\\implies \rm a=\dfrac{10-15}{2}\\\\\implies \rm a=\dfrac{-5}{2}\\\\\implies \rm a=-2.5\ m/s^2$

- ve sign of acceleration denotes retardation / deceleration