Question

1. A particle of mass 2 kg moving on a line
y = x + 5 on x-y plane with velocity 10 m/s.
Angular momentum (in Js) of the particle about
the origin may be given by

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Answer 1

Answer:

50√2 js

Explanation:

the shortest perpendicular distance from origin to the line can be given by....

|y-x-5| / √(1^2+(-1)^2)...... ( a coordinate geometry concept)

here y and x are taken to be 0 since we have to calculate from origin

which gives min. distance to be 5/√2

now

angular momentum =mvr = 2 ×10× 5/√2

=50√2