1. A pendulum has a time period of 2.5 seconds. How many oscillations does it complete in one hour?
An athlete runs 200 metres in 16 seconds. What is his average speed in Sl units?
Answers
Answer:
oscillations in 5 s hence 1 oscillation in 2.5 s which is its time period
T=2π
g
l
2.5=2π
g
l
l=10×
4π
2
6.25
=1.58m
Answer:
The answers are -
- 144 Oscillations
- 12.5 m/s
Step-by-step explanation:
Calculations -
1). Given data - The time period of a pendulum is 2.5 seconds
The pendulum completes one oscillation in 2.5 seconds. Or
The pendulum takes 2.5 seconds to complete one oscillation.
1 oscillation = 2.5 seconds
x oscillations = 1 hour (360 seconds)
x = 360/2.5
x = 144
The pendulum completes 144 oscillations in an hour.
2). The formula for calculation of average speed is v = d/t, where v is the average speed, d is the distance covered, and t is the time taken.
Given data - the distance is 200 meters and the time taken is 16 seconds.
v = d/t
v = 200/16
v = 12.5 m/s
The average speed of an athlete is 12.5 m/s.
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