Question

1) A piece of string was cut into 20 equal pieces. The length of 8such pieces is24/5 m. Find the length of the original piece of string.
​

Answer 1

Answer:

Answer

Let the length of middle piece = x

Then length of longest piece = 3x

Then length of shortest piece = 3x−46

Thus, x+3x+3x−46=80

⇒7x=126

⇒x=18

Hence, shortest piece = 18×3−46=54−46=8 cm

Answer 2

The length of the original piece of string is 7 m.

---------------------------------------------------------------------------------------------

Let's solve the given problem:

The no. of equal pieces cut from the original piece of string = 20

The length of 8 such pieces = $2\frac{4}{5} \:m = \frac{14}{5} \:m$

So, the length of 1 such piece = $\frac{\frac{14}{5} }{8} \:m$

Since the original piece of string is cut into 20 equal pieces therefore if we calculate the length of 20 such pieces of string then we will get the length of the original piece of string.

Now,

The length of 20 such pieces will be,

= Length of the original piece of string

= 20 × length of 1 such piece of string

= $20 \times \frac{\frac{14}{5} }{8} \:m$

= $20 \times \frac{14}{5} \times \frac{1}{8}\:m$

= $\bold{7\:m}$

Thus, the length of the original piece of string is 7 m.

----------------------------------------------------------------------------------------------

Learn more from brainly.in:

brainly.in/question/49594749