Question

1. A pole 3m high casts a shadow √3 m long on the ground, then find the sun's elevation?​

Answer 1

Step-by-step explanation:

$\huge\underline{\underline{\ Question}}$

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1. A pole 3m high casts a shadow √3 m long on the ground, then find the sun's elevation?

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$\huge\underline{\underline{\ Answer}}$

So please refer the attachment...

Here, in this attachment,

For pole,

Base = √3 m

Opposite (height) is = 3 m

We know that=>

$\implies \boxed{ \tan( \theta) = \frac{opposite}{adjcent} } \\ \implies \tan( \theta) = \frac{ \cancel3 }{ \cancel{ \sqrt{ 3} }} \\ \implies \tan( \theta) = \sqrt{3} \\ \implies \huge \boxed{ ( \theta) = 60 = \frac{\pi}{3} }$