1. A PQR, PQ = 5 cm, PR = 7cm, RQ = 8cm
2. A ABC, AB = BC = CA = 5cm
Answers
Answer:Construct Δ XYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm. ... Draw Δ PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. ... Construct Δ ABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. ... To construct: An isosceles triangle PQR where PQ = RQ = 6.5 cm and Ð Q = 1100. ... (a) Draw a line segment QR = 8 cm.
Step-by-step explanation:
Answer:
(a) Draw a line-segment AB and take a point C outside AB.
(b) Take any point D on AB and join C to D.
(c) With D as centre and take convenient radius, draw an arc cutting AB at E and CD at F.
(d) With C as centre and same radius as in step 3, draw an arc GH cutting CD at I.
(e) With the same arc EF, draw the equal arc cutting GH at J.
(f) Join JC to draw a line l.
This is the required line AB || l.
Class_7_Maths_Practical_Geometry_Construction_Of_Parallel_Lines1