Question

1) A Quadratic Equation ax+ bx + c = 0, with b2 - 4ac + 0, will
always have
Roots​

Answer 1

Step-by-step explanation:

We know:

Any quadratic equation can be written in the form of

$ax^{2} +bx+c;a\neq 0$

here

$D = b^{2} - 4ac$

Now when

(i) $b^{2} -4ac > 0$ then REAL & DISTINCT ROOTS exist

(ii) $b ^{2} - 4ac < 0$ then NO REAL ROOTS exist

(iii)$b^{2}- 4ac =0$ then REAL AND EQUAL ROOTS exist

Hope it is helpful

pls mark brainliest