Question

1.A quadratic polynomial, whose zeroes are – 3 and 4 is:

${x}^{2} - x + 12$
${x}^{2} + x + 12$
${x }^{2} - x - 12$
$2 ^{2} + {2}^{2} - 24$
​

Answer 1

(x+3)(x-4)

x^2 - 4x + 3x - 12

x^2 - x - 12

Option : C

Answer 2

Answer:

option c

Step-by-step explanation:

$\alpha = -3 \\\\beta =4\\\alpha +\beta = -3+4 = 1 \\\alpha \beta = 4*(-3) = -12 \\p(x)= x^{2} -(\alpha +\beta )x + \alpha \beta \\= x^{2} -1*x -12\\=x^{2} -x -12$