Question

1.A quadratic polynomial, whose zeroes are – 3 and 4 is:

{x}^{2} - x + 12x2−x+12
{x}^{2} + x + 12x2+x+12
{x }^{2} - x - 12x2−x−12
2 ^{2} + {2}^{2} - 2422+22−24
​

Answer 1

Answer:

x² - x - 12 = 0

Step-by-step explanation:

PLEASE RATE, THANK AND MARK AS BRAINLIEST.

Answer 2

Step-by-step explanation:

the zeroes are -3 and 4

x = -3; x = 4

$x = - 3 \: \: \: \: x = 4 \\ x + 3 = 0 \: \: \: \: x - 4 = 0 \\ (x + 3)(x - 4) = 0 \\ {x}^{2} - 4x + 3x - 12 = 0 \\ {x}^{2} - x - 12 = 0$

hope you get your answer