Question

1. A quadrilateral park ABCD has angle C =90 degree ,AB =13m ,BC=12m,CD=9m and AD=14m. Find it's area.
2.The perimeter of a triangular field is 300 cm and its side are in the ratio 5:12:13.Find the length of the perpendicular from the opposite vertex to the side whose length is 130cm

Please it's urgent
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Answer 1

Answer:

Step-by-step explanation:

by Pythagoras theorem,  

AC = √AB²−√BC²

=√13² - √12²

=√169 - 144

AC = √25 = 5 m

Area of triangle △ABC=1/2×base×height

△ABC=1/2×12 x 5

= 30 m²

NOW, for the area of the triangle, ACD

we will take a = 5 m, b = 14 m  and c = 9 m

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side.

Note: This rule must be satisfied for all 3 conditions of the sides.

in this question a+c=14 m and c=14 m which is not satisfying the condition of triangle.

Answer 2

Answer:

30m sq.

Step-by-step explanation: