1) A rectangle has same area as that of a square of side 10 m. If the breadth of the
rectangle is 8 m, find the perimeter of the rectangle.
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Answers
A rectangle has same area as that of a square of side 10 m. If the breadth of the
rectangle is 8 m, find the perimeter of the rectangle.
Let,
- The breadth of rectangle be x m
★ Area of square = Area of rectangle
Area of square ( side × side ) = Area of rectangle ( length × breadth )
So,
Now,
- Perimeter of rectangle = 2 ( l + b )
- perimeter = 41m²
Answer :
➥ The perimeter of the rectangle = 41 m²
Given :
➤ A rectangle has same area as that of a square of side = 10 m
➤ The breadth of the rectangle = 8 m
To Find :
➤ The perimeter of the rectangle = ?
Required Solution :
❒ In the above Question, we are provided that A rectangle has same area as that of a square of side 10 m, that means Area of rectangle is equal to Area of square whose side is 10 m. And the breadth of the rectangle is 8 m.
✒ To find the, the perimeter of the rectangle. at first we need to find the length of a rectangle to find the length of a rectangle, we will assume the length of rectangle be l m, Then, let's solve the solution on the basis of conditions given above.
Let ,
The length of th rectangle be "l"
As we know that
Area of rectangle = l × b
Here,
- l is the Length in m.
- b is the Breadth in m.
Area of square = a²
Here,
- a is the side in m.
So ,
⇒ Area of Rectangle = Area of Square
⇒ length × breadth = Side²
⇒ l × 8 = 10²
⇒ 8l = 100
⇒ l = 100/8
⇒ l = 12.5 m
Now, we have length and breadth of a rectangle,
- Length of a rectangle = 12.5 m
- Breadth of a rectangle = 8 m
We can find the perimeter of a rectangle by using formula of perimeter of a rectangle which says 2(l + b).
Here,
- l is the Length in m.
- b is the Breadth in m.
✎ So, let's find the perimeter of a rectangle !
⇛ Perimeter of a rectangle = 2(l + b)
⇛ Perimeter of a rectangle = 2(8 + 12.5)
⇛ Perimeter of a rectangle = 2 × 20.5
⇛ Perimeter of a rectangle = 41 m²
║Hence, the perimeter of the rectangle is 41 m².║