1 =A rectangular lawn 70 m by 50 m has two cross roads each 6 m wide running in the middle of it the bar
to the length and other parallel to the breadth. Find the cost of levelling them at $5.50 per square metre.
4. A room 12.5 m long and 10,5 m wide is surrounded by a verandah 2 m wide all around it. Find the
occupied by the verandah.
5 Two cross-roads each of width 5 m run at right angles through the centre of a rectangular park
by 50 m, such that each is parallel to one of the sides of the park. Find the area of the remaining po
of the park
Answers
Answer:
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Step-by-step explanation:
answer 5----
width =5 m
length of first parallel road 70 m
area of first road 70×5=350 sq.m
length of second road 45 m
area of second road =45×5=225 sq.m
area of the common part of cross road with 5 m width that lies at the
center of the park 5×5 = 225 sq.m
area of roads = area of first road +area of second cross road−common area
=(350+225)−25
=575−25
=550sqm
cost of the construction per sq.m =Rs.105
total cost =550×105=Rs 57750
answer 4
Length of room-12.5m
Breadth of room-10.5m
Area-12.5x10.5
=131.25m?
After adding the length of verandah:
=12.5+2+2
=16.5m
After adding the width of verandah:
=10.5+2+2
=14.5m
Area of verandah=16.5x14.5
=239.25m2
Area occupied by the verandah=239.25-131.25
=108m2
..x.....x.......x.......x........x.......x
answer 1---
area of lawn=50*70=3500
area of path= (6*50)+(6*70)-(6*6)
=300+420-36
=720-36
=684m
cost of levelling=684*550/100
=$3420
Answer:
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Step-by-step explanation: