Question

1. A rectangular plate has length (4 +0.04) cm
and width (2 + 0.02) cm. The maximum
percentage error in the measurement of
its area is :​

Answer 1

Answer:

a=lb        

Explanation:

%error=%l+%b              

     =0.04/4×100+0.02/20×100                      

=2%

Answer 2

Answer: 2.01 %

Explanation:

• Given:- Length:- (4+0.04)cm

                     Breadth:- (2+0.02)cm

• To find:- The percentage error in the area of rectangular plate.
• Solution:-

        Original Area= l*b

                              = (4*2) $cm^{2}$

                              = 8  $cm^{2}$

         Area with error= (4.04*2.02)  $cm^{2}$

                                  = 8.1608  $cm^{2}$

        Change in the area= 0.1608  $cm^{2}$

          % change in area= $\frac{0.1608}{8}*100$

                                       = 2.01 %

• Hence, the % error in area is 2.01 %.

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