1. A rhombus shaped sheet with perimeter 24 cm and one diagonal 10 cm , is painted on both sides at the rate of Rs. 5 per cm2. Find the cost of painting
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Solution
One side of rhombus= 24/4= 6cm
Now,,applying Pythagoras theorm in one of the triangle.
side ^2= 5^2+ other ^2
=> 36 = 25+ other^2
=> other^2= 11
=> other= root11
so,,other diagonal= 2root11.
Area= 1/*d1*d2
= 1/2* 2root11* 10
= 10*root 11*2 (both sde area)
20root11 cm^2
cost of painting= 20root11* 5= rs 100*root 11.
One side of rhombus= 24/4= 6cm
Now,,applying Pythagoras theorm in one of the triangle.
side ^2= 5^2+ other ^2
=> 36 = 25+ other^2
=> other^2= 11
=> other= root11
so,,other diagonal= 2root11.
Area= 1/*d1*d2
= 1/2* 2root11* 10
= 10*root 11*2 (both sde area)
20root11 cm^2
cost of painting= 20root11* 5= rs 100*root 11.
Answered by
1
Answer:
One side of rhombus= 24/4= 6cm
Now,,applying Pythagoras theorm in one of the triangle.
side ^2= 5^2+ other ^2
=> 36 = 25+ other^2
=> other^2= 11
=> other= root11
so,,other diagonal= 2root11.
Area= 1/*d1*d2
= 1/2* 2root11* 10
= 10*root 11*2 (both sde area)
20root11 cm^2
cost of painting= 20root11* 5= rs 100*root 11.
Step-by-step explanation:
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