1. A room is 10 metre in length and 8 metre in width. If tiles of 20 cm x 40 cm are used, find the cost
of tiling the room at the rate of Rs 18 per tile.
Answers
Given :
- A room is 10 metre in length and 8 metre in width.
- Tiles of 20 cm x 40 cm are used.
- Cost of one tile is ₹ 18
To Find :
Cost of tiling the room.
Solution :
Analysis :
First we have to find the area of the room. Then the area of the tile. After that by dividing the area of the room by the area of the tile we will get how many tiles. Multiplying the number of tile with the cost of one tile we will get our answer.
Explanation :
- Length = 10 m = 20 × 100 = 1000 cm
- Breadth = 8 m = 8 × 100 = 800 cm
We know that if we are given the length and breadth of the rectangle then our required formula is,
Area of room = Length × Breadth
where,
- Length = 1000 cm
- Breadth = 800 cm
Using the required formula and substituting the values,
⇒ Area of room = Length × Breadth
⇒ Area = 1000 × 800
⇒ Area = 800000
∴ Area of room = 8,00,000 cm².
We know that if we are given the length and breadth of the rectangle then our required formula is,
Area of tile = Length × Breadth
where,
- Length = 20 cm
- Breadth = 40 cm
Using the required formula and substituting the values,
⇒ Area of tile = Length × Breadth
⇒ Area = 20 × 40
⇒ Area = 800
∴ Area of tile = 800 cm².
Number of tiles :
No of tiles = Area of room/Area of tile
where,
- Area of room = 8,00,000 cm²
- Area of tile = 800 cm²
Using the required formula and substituting the values,
⇒ No of tiles = Area of room/Area of tile
⇒ No of tiles = 800000/800
⇒ No of tiles = 1000
∴ No of tiles = 1000 tiles.
Cost :
We know that if we are given the total number of tiles and cost of per tile and is asked to find the cost then our required formula is,
Total Cost = No of tiles × Cost per tile
where,
- No of tiles = 1000
- Cost per tile = ₹ 18
Using the required formula and substituting the values,
⇒ Total Cost = No of tiles × Cost per tile
⇒ Total Cost = 1000 × 18
⇒ Total Cost = 18000
∴ Total Cost = ₹ 18,000.