Question

1. (A) Select and write the most appropriate alternative from those given below:
If a and ß are the zeroes of the polynomial x2 + 6x + 5 then (a +B) =
(a) - 36
(b) -6
(c) 6
(d) 36​

Answer 1

Option (b) is the correct one.

Since we have the form of a quadratic equation as:

${x}^{2} - ( \alpha + \beta )x + ( \alpha \beta ) = 0$

Therefore -(b) = -6 is the answer.

Another way of looking at it is,

x^2 + 6x + 5 =0

x^2 +x + 5x + 5 =0

x(x+1) + 5(x+1) = 0

(x+1)(x+5)=0

Therefore, the roots will be -1 and -5 whose sum is equal to -6 and hence your answer.