Question

1. A ship P sails at a steady speed of 45 km/h in
a direction of W 32◦ N (i.e. a bearing of 302◦)
from a port. At the same time another ship Q
leaves the port at a steady speed of 35 km/h
in a direction N 15◦ E (i.e. a bearing of 015◦).
Determine their distance apart after 4 hours

Answer 1

I am knowing this and bus I am not free now ....sorry. do this ans with your own

Answer 2

Answer:

193 KM

Step-by-step explanation:

After 4 hours, ship P has sailed 180 km, and ship Q 140 km.

Let O be the port of origin.

angle POQ = 58° + 15° = 73°

OP = 180 km

OQ = 140 km

The required distance is PQ.

PQ² = OP² + OQ² - 2(OP)(OQ)cos(POQ)

PQ² = 180² + 140² - 2(180)(140)cos(73°)

PQ² ≈ 37264

PQ ≈ 193 km