Math, asked by Valuu, 1 year ago

1)A shopkeeper bought a wrist watch for Rs.2200 and earns a profit of 10%. Find the selling price of the watch.
2)The price of a scooter is increased by 10% this year. The present price is Rs.40500. What was the last year's price?

Answers

Answered by SidharthaPaul
1
Heya,

1) Price of the watch - Ru. 2200

Profit - 10/100

So, 10/100×2200

= Ru.220

We know,

S.P. = C.P. + Profit / Gain

Hence,

Ru.(2200+220)

= Ru. 2420.

2) Present Price of the scooter - Ru. 40500

% of increased price - 10/100 or 10%

So,

10/100×40500

= 4050

So,

40500-4050

= 36450.


Valuu: Thanks
Valuu: First is correct and second is wrong.
SidharthaPaul: Really?
Valuu: yes
SidharthaPaul: ohh
Answered by ItzAaryan
1

1 ) 2420

2 ) 36450

Hope it helps u........

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