Question

1. A simply supported beam carries uniformly
distributed load of 20 kN/m over the length of
5 m. If flexural rigidity is 30000 kN.m², what
is the maximum deflection in the beam?
a. 5.4 mm
b. 1.08 mm
c. 6.2 mm
d. 8.6 mm​

Answer 1

Answer:

1. A simply supported beam carries uniformly

distributed load of 20 kN/m over the length of

5 m. If flexural rigidity is 30000 kN.m², what

is the maximum deflection in the beam?

a. 5.4 mm

Answer 2

Answer:

The maximum deflection in the beam is 5.4mm i.e.option(a).

Explanation:

The maximum deflection can be calculated as,

$\delta=\frac{5wL^4}{384E}$        (1)

Where,

δ=maximum defection in the beam

w=load supported by the beam

L=length of the beam

E=flexural rigidity

From the question we have,

w=20kN/m

Length of the beam=5m

E=30000kN.m ²

By substituting the value of w, L, and E in equation (1) we get;

$\delta=\frac{5\times 20\times (5)^4}{384\times 30000}$

$\delta=0.0054m$

$\delta=5.4\times 10^-^3m=5.4mm$

Hence, the maximum deflection in the beam is 5.4mm i.e.option(a).