Question

1. A small square is located inside a bigger square. The length of one side
of the small souare is 3 inches and the length of one side of the big
square is 7 inches. What is the area of the region located outside the
small square, but inside the big souare?
2. A classroom has a length of 20 feet and a width of 30 feet The
headmaster decided that tiles will look good in that class. If each tile
has a length of 24 inches and a width of 36 inches how many tiles are
needed to fill the classroom?
3. A room whose area is 22 #2 has a length that is 2 feet longer than the
wioth. What are the dimensions of the room?
4. The length of a rectangle is 6 cm and the width is 4 cm. If the length is
greater by 2 cm what should the widta be so that the new rectangle
have the same area as the first one?
5. A TV has a length of 80 cm and a width of 50 cm. If the border is 5 cm
thickt be the area of the screeni​

Answer 1

Answer:

1. The length of one side of the small square is 3 inches, hence, its area is (3*3)sq.inche =9 sq.inches

The length of one side of the big square is 7 inches, so, the area of the big square is =(7*7)sq.inches=49 sq. inches

By subtracting, ( 49-9)sq.inches=40sq. inches.

Area located outside the small square is 40sq inches & its inside is 9sq.inches gradually.