Physics, asked by jahidmohammad100, 8 months ago

1. A steam engine boiler is maintained at 250°C and water is converted into steam. This steam is used to do work and heat is ejected to the surrounding air at temperature 300K. Calculate the maximum efficiency it can have?

Answers

Answered by Anonymous
20

Answer:

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Answered by alfredrosario
6

Answer:

The maximum efficiency it can have is 42.6%

Explanation:

Carnot Engine:

  • It's a theoretical engine that works on the principle of Carnot's Cycle.
  • The efficiency of this engine depends only on the temperature of the source(T_{i}) and sink(T_{f}).
  • Its efficiency(\eta) is given by

                                     \eta=(1-\frac{T_{f} }{T_{i} })

Step 1:

Given that, the Steam engine boiler is maintained at 250^{\circ}C, which is the temperature of the source. It is also given that heat is ejected at a temperature of 300K, which is the temperature of the sink.

                                     T_{i}=250^{\circ}C\\ T_{f}=300K

Step 2:

The source temperature is in degree Celsius which has to be converted to Kelvin scale. The conversion is given by

                                     T_{K}=273+T_{c}

where T_{K} is the temperature in the Kelvin scale and T_{c} is the temperature in the Celsius scale.

Therefore, converting 250^{\circ}C to Kelvin scale we get,

                                    T_{i}=273+250=523K

Step 3:

Substituting the temperature values in the formula for Efficiency we get,

                                    \eta=(1-\frac{300}{423})\\\eta=(1-0.57)\\\eta=0.426

Step 4:

It is sensible to write efficiency in per cent. Therefore,

                                  \eta=0.426(100)=42.6

Therefore, the maximum efficiency of the steam engine boiler operating between 250^{\circ}C and 300K is 42.6%

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