Question

1) A stone falls from a cliff and travels 34.3m in the last second before it reaches the ground.

Calculate the height of the cliff.

Answer 1

Hey friend,

Here's your answer,


Let the height of the cliff be 'h'

Let the time taken to reach the cliff be 't'


Therefore, it takes t seconds to cover the distance of 34.3 m.


Using,


St = u + (a/2)(2t – 1)

= 34.3 = 0 + (9.8/2) (2t – 1)

t = 4 s

Now,

Using the second equation of motion,

S = ut + ½ at²

h = 0 + ½ × 9.8 × 42

h = 78.4 m



Hope this helps!!!!

Answer 2

Using,

St = u + (a/2)(2t – 1)

= 34.3 = 0 + (9.8/2) (2t – 1)

t = 4 s

Now,

Using the second equation of motion,

S = ut + ½ at²

h = 0 + ½ × 9.8 × 42

h = 78.4 m

#be_brainly