Question

1. A stone is dropped from the edge of a roof and passes a window that is 1 m high in 0.15.
How far is the roof above the top of the window? (Take g =
10 m/s​

Answer 1

Taking the time for travel to the window top on its free fall of stone be t=> the covering of the window length of 2m by the stone could have an eqn of path as 2={(gt+gt+g×0.1)/2}×0.1

Solving the eqn could bring 2=g(t+0.05)×0.1=>

20=g(t+0.05)=>t={2–0.05}=1.5s.Hence the height of roof above window is the distance of free fall from roof to window top in the above available time.Hence the height=(1/2)×10×1.5²

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