1. A stone is dropped from the top of a building 200 m high and at the same time another stone is projected vertically upward from the ground with a velocity of 50 ms. find where and when the two stones will meet.
2. A ball thrown vertically upward reaches a height of 80 m. calculate
A. the time of reach the highest point.
B. the speed of the ball upon arrival on the ground.
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1. Let distance travelled by 1st stone is x.
Distance travelled by 2nd stone is 200-x.
For 1st stone, u=0
x=1/2 gt^2
And for 2nd stone, u=50m/s
200-x =50t-1/2 gt^2
Adding both the equations,
200=50t
t=4 sec
Hence the two stones will meet after 4 s.
And x=1/2×10 ×4^2=80m
200-x= 120m
Hence 1st stone will travel 80m and 2nd will travel 120m.
Distance travelled by 2nd stone is 200-x.
For 1st stone, u=0
x=1/2 gt^2
And for 2nd stone, u=50m/s
200-x =50t-1/2 gt^2
Adding both the equations,
200=50t
t=4 sec
Hence the two stones will meet after 4 s.
And x=1/2×10 ×4^2=80m
200-x= 120m
Hence 1st stone will travel 80m and 2nd will travel 120m.
priyanshukishu1:
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