Question

1. A stone is projected with velocity 50 m/s at angle 60° to
the horizontal. What will be the speed of stone at the time
when it makes angle 30° with horizontal?​

Answer 1

Answer:

stone is projected with speed of 50ms−150ms-1 at an angle of 60∘60∘ with the horizontal. The speed of the stone at highest point of trajectory is

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Text Solution

75ms−175ms-1

25ms−125ms-1

50ms−150ms-1

cannot find

Answer :

B

Solution :

At highest point, vertical component of velocity is zero. Only horizontal component of velocity is present. vx=ucosθ=50cos(60)=25ms−1

Step-by-step explanation:

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