Question

1. A stone is thrown up with speed of 0.5 m/s2. How high will the stone go before it
begins to fall?

Answer 1

Answer:

5.1m

Explanation:

For this problem we have to use the formula :

v^2 −u^2=2aS

Here, v=0, at highest point the velocity of stone is zero and

a=g=9.8,u=10m/s and S=h

Thus, 0 ^2−10 ^2=2(9.8)h or h=5.1m