1. A stone is thrown vertically upwards with a velocity of 4.9m * s ^ - 1 . Calculate (i) the maximum height reached (ii) the time taken to reach the maximum height (iii) the velocity with which it returns to the ground and (iv) the time taken to reach the ground.
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Answer:
Given infomrations are
• v- 0
• u-49m/s
• a-10m/s2s2
Using the formula v=u + at. We get,
t=v−uav−ua
=−49−9.8−49−9.8
=5 s
S=ut + 0.5at2t2
=49 x 5 + (-4.9) x5252
= 122.5 m
Time taken to go up = time taken to come down
Therefore, time taken to come down
= 5 sec
Total time taken
= 10 sec
And the distance will be
= 122.5 m
Explanation:
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