Question

1. A stone thrown vertically upwards, takes 3 s to attain maximum height. Calculate (i) initial velocity
of the stone (ii) maximum height attained by the stone. (Take g = 9.8 ms)
(i) 29.4 ms' (ii) 44.1 m)​

Answer 1

Answer:

Calculate initial velocity of the stone maximum height attained by the stone. (Take g = 9.8 ms −2) Concept: Rate of Change of Velocity.

Explanation:

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Answer 2

Answer:

Let,

u  = Initial velocity of stone

H  = Maximum height attained by the stone

v = final velocity at maximum height = 0

t  = time taken to attain maximum height = 3s

a=−g= acceleration due to gravity

(i) We know that,

v=u+at 

0=u−g×3 

u=3g=3×9.8ms−2 

u=29.4ms−1 

(ii) From the equations of motion , we know that , 

 

 s=ut+21at2 

H=29.4×3+219.8×9 

H=88.2+44.1 

H=132.3m 

Explanation:

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