1)A student recorded the weight of dry raisins as 5.4 gm and on soaking them for 4 to 5 hours the weight was 7.6 gm. Calculate percentage of water imbibed by the raisins.
2)In a cricket match why does a player lower his hands slightly while catching the ball.
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to reduce the force of a ball
to reduce the force of a ball
saitejach88:
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1. mass of dry raisins = 5.4 g
mass of raisins after soaking = 7.6g
mass of water imbibed = 7.6 - 5.4 = 2.2g
percentage of water imbibed = (2.2/5.4)*100 =40.74%
2. When the player lowers his hand, it increases the time of catching. And hence the force acting on the hand reduces. So to reduce the force, he lowers his hand.
mass of raisins after soaking = 7.6g
mass of water imbibed = 7.6 - 5.4 = 2.2g
percentage of water imbibed = (2.2/5.4)*100 =40.74%
2. When the player lowers his hand, it increases the time of catching. And hence the force acting on the hand reduces. So to reduce the force, he lowers his hand.
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