Question

1
A student used sulfuric acid instead of nitric acid in her experiments. She
started with 25.0 cm of sulfuric acid of concentration 0.650 mol/dm'.
She added 0.500 mol/dm sodium hydroxide solution until the acid was
completely neutralised.
The equation for this reaction is
2NaOH + H,SOA → Na SO, + 2H,0

(i) Calculate the amount, in moles, of sulfuric acid used.
(ii) Calculate the amount, in moles of sodium hydroxide needed to neutralise this amount of sulfuric acid
(iii) Calculate the volume, in cm3, of sodium hydroxide solution needed to neutralise this amount of sulfuric acid

Answer 1

Answer:

1) 0.01625 moles--------->   25×0·625/1000

2)0.0325 moles ----------->0.01625×2

3)71 cm³ -------------->0.0355÷0.500×1000

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Explanation: