Question

1) A student walks from his house at 7:45 a.m.and reaches his school at 9:15 a.m.the distance of the school from his house is 12 km.find the speed of the student.
2) A person covered a distance of 390 km by a car in 6h 30 min.calculate the speed. pls answer in detail step by step

Answer 1

1. To find the time we should subtract the final time from initial time = 9:15-7:45.
The time gap between them is 1h 30 minutes=1.5hours.

Distance is given as 12km.

So, speed= distance/time=12/1.5=8km/hr.

Speed of the student=8km/hr.

2. Distance is given as 390km.

Time is given as 6 hours 30 minutes=6.5 hours.

Speed= distance/time=390/6.5=60 km/hr.

Speed of the car = 60 km/hr.

Answer 2

Bonjour!

1) According to the question, A student walks from his house at 7:45 a.m.and reaches his school at 9:15 a.m.the distance of the school from his house is 12 km.

So, the time taken by the student to travel 12 km = 9:15 - 7:45

= 1 hour 30 minutes

= 1.5 hour

$speed = \frac{distance \: }{time}$

Given distance = 12 km
So,

$= > speed = \frac{12}{1.5} \\ \\ = > speed= 8 \: km/hr$

2) According to the question, A person covered a distance of 390 km by a car in 6h 30 min.

Given distance = 390 km
Time = 6 h 30 min

= 6.5 hour

So,
$= > speed = \frac{distance}{time} \\ \\ = > speed = \frac{390}{6.5} \\ \\ = > speed =60 \: km/ h$

Hope this helps...:)