Math, asked by ashikakhadka6, 4 months ago

1. a) Sunayana distributed (3x + 20x + 25) sweets equally among (3x + 5) friends
fi) How many sweets did each of the friends receive?
(ii) If x = 5, find the total number of sweets distributed among friends, actual
number of friends and share of sweets.​

Answers

Answered by riyaverma9490
1

Step-by-step explanation:

(3x + 20x + 25) =( 3x + 5)

23x + 25 = 3x + 5

23x - 3x = 5 -25

20x = -20

x = -20/20

x = -1

(I) is x = -1

Then total sweets= 3(-1) + 20(-1) + 25

= -3+(-20)+25

= -3-20+25

= -23+25

= 2 sweets

Total friends = 3(-1) +5

= -3+5

= 2 friends

so ,sweets, each of the friends receive

= total sweets/ total friends

= 2/2

= 1

Ans. Each friends recieve 1 sweets.

(ii) x = 5, the total number of sweets

3(5) + 20(5) + 25

15+ 100+ 25

140

Total no. of friends

3(5) + 5

15+5

20

the total number of sweets distributed among friend

140/20

7

(ii) The total number of sweets distributed among friends is 7.

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