(1)A tall green pea plant that is homozygous dominant for both traits(TTGG) is crossed with a short yellow (ttgg) pea plant that is homozygous recessive for both traits.
Draw the Punnett square and determine the possible offspring phenotype.
(2) Find the genotypic ratio too.
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Answer:
The genotypic ratio will be written as 4:0:0:0 or 4 TtGg : 0 TTGG : 0 ttgg : 0 Ttgg.
Explanation:
From the above question,
They have given :
A tall green pea plant that is homozygous dominant for both traits(TTGG) is crossed with a short yellow (ttgg) pea plant that is homozygous recessive for both traits.
| T T G G
t | TtGg TtGg TtGg TtGg
t | TtGg TtGg TtGg TtGg
g | TtGg TtGg TtGg TtGg
g | TtGg TtGg TtGg TtGg
Possible offspring phenotypes:
All offspring will be tall (due to homozygous dominant trait for height)
All offspring will be inexperienced (due to homozygous dominant trait for color)
Therefore, all the offspring will be tall and green.
The genotypic ratio will be:
4 TtGg : zero TTGG : 0 ttgg : zero Ttgg
Simplifying,
It can be written as 4:0:0:0 or 4 TtGg : 0 TTGG : 0 ttgg : 0 Ttgg.
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