Question

1. A tent is in the form of a right Circular Cylinder
Surmounted by a cone The diameter of cylinder is 24m.
The height of the Cylindrical portion is 11m while the
vertex of the Cone is 16m above the ground find the area of Canvas required for the tent​

Answer 1

Step-by-step explanation:

Area of canvas required for the tent = Curved surface area of the cylindrical portion + Curved surface area of the cone

=(π)rl+2(π)rh

For cylinder:

Radius (r) of the cylinder =12 m

Height(h) of the cylinder =11m

Curved surface area of cylinder =2πrh=2(π)×12×11=264(π)

For cone:

Height (h) of the cone = Height of the vertex from ground − Height of the cylinder

=16−11=5 m

Radius (r) of the cone =12m

Slant height of the cone =lm

l

2

=r

2

+h

2

l=

r

2

+h

2

l=

5

2

+12

2

=13m

Curved Surface area of cone =πrl=π(12)(13)=(156π)m

2

Hence, area of canvas =(264π+156π)m

2

=(420π)m

2

=420×

7

22

=1320m

2

.