1) A toy is in the form of a cylinder of diameter 2root2 m and height 3.5 m surmounted by a cone whose vertical angle is 60degree .Find total surface area and volume of the toy.
2)three cubes of a metal whose edges are in the ratio 3:4:5 are melted and converted into a single cube whose edges is 12cm Find the edge of the three cubes.
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1)
SEE THE ATTACHED IMAGE
Angle FAC = 30
In triangle FAC
Sin A = CF/AC = √2/AC
AC = 2√2
Cos 30 = AF/AC
√3/2 x 2√2 = AF
AF = √6
Surface area = 2(pi)rh + (pi)rl + (pi)r²
= 2(3.14)(√2)(3.5) + 3.15(2)(√2)² + 3.15(√2)²
= 44.67 m²
Volume = 1/3(pi)r^2h + )pi)r²H
= (pi)r²(1/3h + H)
= 3.14(√2)^2(1/3 x√6 + 1.3)
= 13.29 m³
2)
Take the dimensions of the cubes to be 3x, 4x and 5x respectively
Total volume of the small cubes = volume of the big cube
(3x)³ + (4x)³ + (5x)³ = 12³
27x³ + 64x³ + 125x³= 1728
216x³ = 1728
x³ = 8
x = 2
So, the edge of the small cubes = 3(2), 4(2) and 5(2)
= 6 cm by 8 cm by 10 cm
SEE THE ATTACHED IMAGE
Angle FAC = 30
In triangle FAC
Sin A = CF/AC = √2/AC
AC = 2√2
Cos 30 = AF/AC
√3/2 x 2√2 = AF
AF = √6
Surface area = 2(pi)rh + (pi)rl + (pi)r²
= 2(3.14)(√2)(3.5) + 3.15(2)(√2)² + 3.15(√2)²
= 44.67 m²
Volume = 1/3(pi)r^2h + )pi)r²H
= (pi)r²(1/3h + H)
= 3.14(√2)^2(1/3 x√6 + 1.3)
= 13.29 m³
2)
Take the dimensions of the cubes to be 3x, 4x and 5x respectively
Total volume of the small cubes = volume of the big cube
(3x)³ + (4x)³ + (5x)³ = 12³
27x³ + 64x³ + 125x³= 1728
216x³ = 1728
x³ = 8
x = 2
So, the edge of the small cubes = 3(2), 4(2) and 5(2)
= 6 cm by 8 cm by 10 cm
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