Question

1. A train begins a journey from a station and travels 60km in a time of 20 minutes. What is the average speed of the train? (answer in meter)

Answer 1

AnswEr:-

The Required Answer Is 50 meter (or metre) per second.

ExplanaTion:-

Given:-

• Total distance of journey of the train = 60 km.

• Time taken to complete the journey = 20 minutes.

To Find:-

• The Average speed of the train (in meters).

Formula Used:-

${\rm\longrightarrow\boxed{\bf S = \dfrac{D}{T}.}}$

Where,

• S = Speed.

• D = Distance.

• T = Time.

Concepts Used:-

• 1 kilometer = 100 meters.

• 1 Minute = 60 Seconds.

So Now,

$\because$ We have to Find out the Average speed in meter per second So let us first convert 60 km in meters amd 20 minutes in seconds.

$\tt\mapsto 1 \: km = 1000 \: m.$

$\tt\mapsto1 \: km\times 60 = 1000 \: m \times 60.$

$\rm\big(multiplying \: \: 60 \: \: both \: \: the \: \: sides \big).$

${\bf\mapsto \boxed{ \bf60 \: km = 60000 \: m.}}$

Similarly,

$\tt\mapsto1 \: \: min = 60 \: \: sec$

$\tt\mapsto1 \: \: min \times 20 = 60 \: \: sec \times 20.$

$\rm \big(multiplying \: \: 20 \: \: both \: \: sides \big).$

${ \bf\mapsto \boxed{ \bf20 \: \: min = 1200 \: \: sec.}}$

Therefore,

${\underline{\underline{\bf Average \ \ Speed\ \ Of\ \ The\ \ Train:-}}}$

$\tt = \dfrac{600 \cancel{00} \: \: \cancel{m}}{12 \cancel{00} \: \: \cancel{sec}} .$

$\tt = \dfrac{ \cancel{600} \: \: {}^{50} }{ \cancel{12} \: \: _1}$

${ \boxed{ \bf =50 \: m/s}}$

$\large\bf\therefore$ The Average Speed Of the Train = 50 meter per second.