Question

1. A train crosses 80 metre long platform in 30
seconds. If the speed of the train is 4 m/s, what
is the length of the train?​

Answer 1

Answer:

distance =speed ×time

4×30=120

so length of the train is 120-80=40

Answer 2

Answer:

Time difference while crossing platform and a signal is 30 - 12 = 18s.

=> Train travels 300m in 18s

=> Speed of train = 300/18 x 18/5 = 60 km/hr.

=> Length of train = 300/18 x 12 = 200m.

Traditional Method

Let length of train = L metres and speed = S m/s

Train covers (300 + L) metres in 30 seconds.

=> Speed of train = (300 + L)/30

Further, train covers L metres in 12 seconds.

=> Speed of train = L/12

Now, (300 + L)/30 = L/12

=> 3600 + 12L = 30L

L = 3600/18 = 200 m

Speed = 200/12 x 18/5 = 60 kmph

:-)

A train passes a 90 m platform in 30 seconds and a man in 15 seconds. What is the speed of train (m/s)?

A train of 100 m length crosses a pole in 10 seconds. What is the speed of the train?

A 300-metre long train crosses a platform in 39 seconds while it crosses a post in 18 seconds. What is the length of the platform?

A train crosses a pole in 40 seconds, while it crosses a 100-meter long platform in 200 seconds. What is the length of the train?

A train running at the speed of 60 km/h crosses a 200 long platform in 27 s. What is the length of the train?

First, let’s find the speed of the train.

Speed = Distance / Time = 300 m / 30 s = 10 m/s

To convert into km/h, simply multiply the speed by 3600 (number of seconds in an hour)

10 m/s = 10x3600 m/hr = 36 km/hr

Now, to find the length of the train, let’s assume that the length of the signal is negligible. Since it takes 12 seconds for the train to cross the signal travelling at a speed of 10 meters per second, the length of the train is 120 m.

Speed of train = 36 km/hr

Length of train = 120 m

Which is the fastest scientific calculator for engineering?

The train actually covers 300 m and its length in 30 sec, and it covers its length in 12 sec .

so it covers 300 m in (30–12)=18 sec .

in 18 sec it covers 300 m

so in12 sec it will cover (300×12)/18= 200 m

length of the train =200 m

speed of the train=300/18 m/sec =(300×60×60)/(18×1000) km/hr =60km/hr .

Assumptions

1 .Train speed is uniform

2.Signal has no length.

To cross tunnel train hato run its own length +300m

To cross signal it has to run its own length

Hence time to travel 300 ms is 30–12 secs.

Speed solved and length solved.

Step-by-step explanation:

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